10+10x-200x^2=0

Solution for 10+10x-200x^2=0 equation:

10+10x-200x^2=0

a = -200; b = 10; c = +10;
Δ = b2-4ac
Δ = 102-4·(-200)·10
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-90}{2*-200}=\frac{-100}{-400}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+90}{2*-200}=\frac{80}{-400}
=-1/5
$